A Mellin Transform Hidden in the Prime Distribution


 

Today we develop a novel analytic framework linking the prime counting function π(x), the Prime Zeta function P(s), and the Riemann zeta function through Mellin-transform techniques and a Prime Counting Correction Formula. 

Building from Abel summation, Stieltjes integration, and distributional representations of prime counting, we derive integral identities that express prime sums directly in terms of π(x) and establish analytic properties of the associated correction term. These results culminate in a Mellin transform representation, revealing how successive smoothing operators applied to the prime distribution encode information about the zeros of the Riemann zeta function.



Lemma 1: Consider the integral

if  then since , we have  and

Thus,

and the two integrals

have the same convergence behavior.

Now

obviously converging if , that is,

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Lemma 2:  counts the total number of primes less than or equal to .

When  is a prime number (),  increases by  relative to , so:

When  is composite number or ,  does not change, so:

The expression

where the summation is over prime numbers, is equal to

Instead of summing only over prime indices, we can sum over all integers  and use the indicator  to filter out non-primes.

In “The Riemann Hypothesis Revealed” you find details about Abel’s Identity:

where  .

Take . Then . Thus, for an arithmetic function  we have

Since

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Lemma 3: Another expression of  is:

where  is the Heaviside step function:  and . Since the distributional derivative of the Heaviside function is

we get

where  is the Dirac delta function.

Note: The formal definition of the Dirac delta function is often given by its behavior under integration:

And for any function  continuous at the origin:

This means that the Dirac delta function "picks out" the value of a function at  when integrated with that function.

The derivative of a distribution is defined by  which is consistent with the formal definition of integration by parts and the behavior of the test function at infinity.

So, for  i.e., vanishing at infinity,

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Lemma 4: Recall that for an ordinary integral , you add up  weighted by tiny intervals . For a Riemann- Stieltjes integral, , you add up  weighted by the increments .

Consider the Prime Zeta function

Take . Since  is constant except at primes, its increments are  at each prime , and  elsewhere. Therefore, the Stieltjes integral becomes (see Lemma 3)

For ,

Applying integration by parts for Riemann-Stieltjes integrals:

Thus,

because moving  to the left gives .

Let  and

The right-hand side integral

 is the Mellin transform of  at   (  ).

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Lemma 5: Take the right-hand side of

(see Lemma 4), and write

We cannot break this into two integrals like

unless these integrals converge. It turns out that this is the case.

Two relatively long steps!

Step 1:  For

Recall (see The Riemann Hypothesis Revealed), the Euler product formula for the Riemann zeta function, valid for :

Since an absolutely convergent infinite product of non-zero terms is strictly non-zero,  for ,

we can analyze its logarithm. We have . Thus, we can apply the Taylor series expansion:

for , i.e.,

and

The theory of prime numbers is largely concerned with the function , the number of primes not exceeding . We can express the outer sum over all integers

Indeed, (see Lemma 2 above) the original expression

is a sum restricted purely to prime numbers . Using Lemma 2

Applying Abel’s Identity (Lemma 2) for  and  , we have

and

But  for , so

Since

Therefore,

and we have

implying

Step 2:

Let

 is analytic and bounded for .

Indeed,

and for

hence

But for  (see Lemma 1 above),

converges if .

So, for some

and we have that the Prime Counting Transform

is analytic for .

Thus, the Prime Counting Correction Formula

is valid.

Additionally,

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Lemma 6:  is analytic in the same region

Write

Differentiating with respect to ,

so

provided the differentiated integrand is dominated by an integrable majorant.

Indeed, for

For

because we can bound

Since

Thus,

But , hence

and by the Weirerstrass -test for improper integrals,

converges uniformly because we can bound its integrand by an integrable function that is independent of .

Thus, differentiation under the integral sign is justified, and  is analytic in the same region .

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A Mellin Transform Representation Derived from the Prime Counting Correction Formula

We can differentiate the Prime Counting Correction Formula

The result is:

or

 

Note: In Season 2 Episode 4, we saw that

where on the right-hand side,  is the well-known arithmetic function called the Mangoldt function, which returns  when  (i.e., a power of a prime number), and zero otherwise.

Thus,

 

Integrating by parts (using  where  and )

Let

Then we write

Clearly . When infinity meets zero, the outcome usually depends entirely on a "tug-of-war" (growth rate) between the two terms to see which one wins. We have  because  is not just approaching zero, it is identically equal to zero. Therefore, before  ever has a chance to grow infinitely large, it is multiplied directly by  at every single point near zero. That kills the product immediately, making the limit  regardless of how large or small  is.

Additionally,

hence

because .

Thus,

Integrating by parts again

To verify that

observe that since  for , . Let

Then  for  and   regardless of . Additionally,  as

Thus,

So

Notice that

But

or

Replace  with  to get the Mellin transform

and let for convenience 

Therefore,

A very nice Mellin Transform.

In “The Riemann Hypothesis Revealed” I derive the Mellin transform from Fourier Transform. The derivation shows that the Mellin transform arises naturally when we shift perspective from additive to multiplicative structures. By making the substitution , we convert multiplication into addition and reveal the Mellin transform as a kind of “logarithmic Fourier transform”—one suited for analyzing how functions behave under scaling rather than shifting.

The sequence of nested integrals

is built from  which weighs the prime distribution by its logarithmic density. Then  and  act as successive smoothing or summation operators over the multiplicative scale.

Taking the Mellin transform of such nested structures naturally yields meromorphic functions with poles encoding the zeros of Zeta

   

   


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