A Small Taste from My New Book: Season 2 Episode 9

 


Today we redraw our attention to Perron’s formula, a powerful bridge between Dirichlet series and arithmetic sums.

Starting from a general Dirichlet series, we develop the machinery needed to recover partial sums via complex integration.

We then present a fully rigorous proof—one you won’t want to miss.

  

Let  and

be a Dirichlet series. There exists a real number  (the abscissa of convergence) such that the series converges for all  and diverges for all . On the open half-plane  the function  is analytic. In The Riemann Hypothesis Revealed, the treatment of Dirichlet series is intentionally concise. Rather than pursuing a general theory, I focus on convergence established through bounded partial sums,

for some . Under this condition, one obtains a proof of the following theorem (see The Riemann Hypothesis Revealed: Dirichlet Series).

 

A Dirichlet series,  with bounded partial sums for some ,

has a half-plane of convergence consisting of all complex numbers such that , where  is the real part of  and  is the abscissa of convergence. Within any closed and bounded subset (i.e., a compact subset) of this half-plane of convergence the series converges uniformly.

 

Let’s start with the following exercise (from the book):

Exercise: Assuming the convergence of  with , prove that

where . Hint: Take Abel’s summation formula with . From this deduce that

Solution: Let . Abel’s summation formula (see The Riemann Hypothesis Revealed) states that

Let , . Then since

We are given that the Dirichlet series  converges. Hence the “tail” term must vanish:

Applying this limit to our equation:

Thus, we arrive at the desired identity:

For  notice that  and for  ( has ) and the comparison test, the integral

converges ().

Note that the condition  implies that  is bounded, which in turn guarantees the existence of the integral

Indeed, if  we may take .  Convergence then ensures that the partial sums are bounded, so there exists  such that

A classical identity in complex analysis expresses the Heaviside step function as the inverse Mellin transform of . Specifically, the integral

i.e., equals  for ,  for , and  at  This formula (see The Riemann Hypothesis Revealed for a proof), plays a central role in explicit formulas in analytic number theory, where constant and slowly varying analytic terms yield step-function contributions in the variable .

Recalling The Riemann Hypothesis Revealed (or any standard reference), the Mellin transform and its inverse are given by

Thus the inverse Mellin transform satisfies .

The key is understanding that this integral is an inverse Mellin Transform.

For this let’s define the slightly modified Heaviside step function shifted to the right by :

Then the Mellin transform of  is:

This integral converges for  and gives:

The inverse Mellin transform for  is:

Now let  and note that for

and the formula to be proved is

Τhis is an inverse Mellin transform.

You may find the proof in the book.

Note: The preceding paragraph contained an incorrect argument in the original text—an all-too-human error made during late-night writing. This correction (shown here in blue) will be included in the next updated edition on Amazon.

The integral

plays a key role in the derivation of the well-known Perron’s formula

The prime on the summation indicates that the last term of the sum must be multiplied by  when  is an integer.

Additionally

is absolutely convergent for   and

As I state in the book, from

we get:

If we substitute

into the integral

This argument is intentionally motivational rather than complete. Its role is not to provide a fully rigorous proof under minimal hypotheses, but to explain why the resulting formula should be true and how it naturally arises from Mellin inversion and Dirichlet series manipulations.

The computation illustrates the underlying mechanism: the inverse Mellin transform produces a Heaviside function that truncates the Dirichlet series, thereby converting an analytic object into a finite sum. Interchanging the order of summation and integration, as well as the growth and convergence conditions required to justify this step rigorously, are not addressed here.

Thus, this derivation should be read as a heuristic roadmap. It guides the reader toward the correct statement and clarifies the analytic structure behind it, leaving the full justification to later sections or to the standard machinery of analytic number theory. For the purposes of this book, this level of explanation is both sufficient and instructive.

Main topic: The technical details, avoid the interchange of the order of summation and integration. Let’s see how.

Consider the series

with abscissa of convergence  and . Perron’s formula holds for the first sum because, in the case of a finite sum, the integral may be brought inside the summation. Consequently, it is enough to prove that the tail sum vanishes as  grows.

Take Abel’s summation formula (see The Riemann Hypothesis Revealed: A path from Numbers to Asymptotic Summation) for the second sum with ,  and .

Set

Clearly

Hence

But we can find ,  such that

From this we get

which tends to

for .

Since  and  we just need to ensure that .

Therefore, to be safe,

This bound will be crucial in what follows.

Now assume  .  

To estimate

for  we fix a large  and compute

This sum is equal to

according to Cauchy’s theorem.

We have

because .

Change the variable to  so

Recall that for

Now estimate  where .

We have  so

Thus,

and

But ,  and , it follows that . Therefore, we may continue with the estimate  

Choose . Then as  

so the whole quantity tends to

Because  , the expression vanishes as  becomes large.

Therefore,

A similar estimate holds for

It remains to verify that the same conclusion applies to

We have  and the integral is equal to

Now again

Hence

Recall that , so

Thus,

Because , this expression likewise vanishes in the limit.

The proof of Perron’s formula is now complete.

 

Epilogue — Season 2, Episode 9

We end this episode having closed the contour, controlled the tails, and fixed a small—but instructive—misstep along the way. As often happens in analytic work, the argument only settles once every estimate is pushed to its limit and every assumption made explicit. Episode 9 stands as a reminder that progress in mathematics is rarely linear: refinement, correction, and clarity are part of the process.

If you enjoyed this deep dive, there’s much more waiting for you in the blog.
These posts are designed to complement a full, rigorous treatment in the book—where results like Perron's formula are developed in complete detail, step by step.
Stay tuned and explore further—this is just a glimpse of the ideas that unfold in the full text.

 

 

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